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PHP Laravel Join with subquery Query Builder

Today, We want to share with you PHP Laravel Join with subquery Query Builder.In this post we will show you PHP Laravel select with join subquery example, hear for Laravel Fluent Query Builder Join with subquery we will give you demo and example for implement.In this post, we will learn about Laravel 5.8 Join with subquery in Query Builder with an example.

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PHP Laravel Join with subquery Query Builder

There are the Following The simple About PHP Laravel Join with subquery Query Builder Full Information With Example and source code.

As I will cover this Post with live Working example to develop Laravel – How to make subquery in select statement?, so the join with select query laravel 5.8 for this example is following below.

Simple MySQL Query:

SELECT
  members.*, member_age.height_group
FROM
  members
INNER JOIN (SELECT 
      member_age.id_member,
      GROUP_CONCAT(member_age.height) as height_group
      FROM member_age
      GROUP BY member_age.id_member) AS member_age
      ON member_age.id_member = members.id
GROUP BY members.id

simple Laravel As We can below display above simple sql query now we MySQL DB query convert into laravel latest version of the db query.

Laravel Convert DB Query:

$data = DB::table("members")
  ->select("members.*","member_age.height_group")
  ->join(DB::raw("(SELECT 
      member_age.id_member,
      GROUP_CONCAT(member_age.height) as height_group
      FROM member_age
      GROUP BY member_age.id_member
      ) as member_age"),function($join){
        $join->on("member_age.id_member","=","members.id");
  })
  ->groupBy("members.id")
  ->get();
print_r($data);

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