Today, We want to share with you PHP Laravel Join with subquery Query Builder.In this post we will show you PHP Laravel select with join subquery example, hear for Laravel Fluent Query Builder Join with subquery we will give you demo and example for implement.In this post, we will learn about Laravel 5.8 Join with subquery in Query Builder with an example.
PHP Laravel Join with subquery Query Builder
There are the Following The simple About PHP Laravel Join with subquery Query Builder Full Information With Example and source code.
As I will cover this Post with live Working example to develop Laravel – How to make subquery in select statement?, so the join with select query laravel 5.8 for this example is following below.
Simple MySQL Query:
SELECT members.*, member_age.height_group FROM members INNER JOIN (SELECT member_age.id_member, GROUP_CONCAT(member_age.height) as height_group FROM member_age GROUP BY member_age.id_member) AS member_age ON member_age.id_member = members.id GROUP BY members.id
simple Laravel As We can below display above simple sql query now we MySQL DB query convert into laravel latest version of the db query.
Laravel Convert DB Query:
$data = DB::table("members") ->select("members.*","member_age.height_group") ->join(DB::raw("(SELECT member_age.id_member, GROUP_CONCAT(member_age.height) as height_group FROM member_age GROUP BY member_age.id_member ) as member_age"),function($join){ $join->on("member_age.id_member","=","members.id"); }) ->groupBy("members.id") ->get(); print_r($data);
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