Python Program to Check Armstrong Number

Today, We want to share with you armstrong number in python.In this post we will show you python program to print the first armstrong number in a given range, hear for Python Program to check whether the given number is Armstrong or not we will give you demo and example for implement.In this post, we will learn about Check Armstrong Number In GO Program with an example.

Python Program to Check Armstrong Number

153 = 1*1*1 + 5*5*5 + 3*3*3  // 153 is an Armstrong number.

Input:

Give Any the number: 407

Output:

Armstrong Number

Input:

Give Any the number: 925

Output:

Not an Armstrong Number

Example 1:

num = int(input("Give Any a number: "))  
sum = 0  
unknow = num  
  
while unknow > 0:  
   digit = unknow % 10  
   sum += digit ** 3  
   unknow //= 10  
  
if num == sum:  
   print(num,"is an Armstrong number")  
else:  
   print(num,"is not an Armstrong number")  

Python program to print Armstrong numbers within the given range in Python

Example 2:

Read Also:  How to get the first word in a string Python?

Input:

Give Any lower range: 100

Give Any upper range: 500

Output:

153 370 371 407

#program to print Armstrong numbers within the given range in Python
lower = int(input("Give Any lower range: "))
upper = int(input("Give Any upper range: "))
for num in range(lower, upper + 1):
    order = len(str(num))
    sum = 0
    #find the sum of the cube of each digit
    unknow = num
    while unknow > 0:
        digit = unknow % 10
        sum += digit ** order 
        unknow //= 10
    if num == sum:
        print(num, end = ' ')

I hope you get an idea about python program to find armstrong number in an interval.
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