Posted inJavaScript / jQuery

println javascript – js println with js Output

println javascript or js println – console.log(“Who’s Joe?”) in javascript print. println() prints a new blank line and then your message.

println javascript – JavaScript Program To Print Hello World


System.out.println("Welcome To Pakainfo");

Javascript Console Log

   Print Console -

javascript system.out.println

public static void main(String[] args){
	System.out.println("Welcome to"); 

Using alert()

the first welcome program

alert("Welcome, pakainfo!");

Using document.write()

document.write('Welcome, pakainfo!');
function Member() {}

Here, you make a function “Member”, which does nothing, and return nothing.
There is not much to say : you can make empty functions with js, that’s all.

Now :

var member = Member()

“Member()” will eval “Member” with no argument, and return its return value : undefined. “=” will assign to the left-operand (member here) the value of the right-operand (undefined here).
So, after that, member will be equal to undefined.

var member = new Member()

which is the same as
var member = new Member
But it is totally unrelated to “var member = Member()”. So, it is quite confusing.

The operator new is rather complicated.

“var object = new Constructor(arguments)” will do many things :
1. It will make an empty object
2. It will set its property “__proto__” to Constructor.prototype, as well as its property “constructor” to Constructor.
3. It will call the function Constructor with the arguments “arguments”, as well as the “this” object set to the object constructed at #1.
4. When the function returns / ends, it will return “this” / the object created at #1. (It is the same, because “this” cannot be changed. You can not do “this = {}” as it will trigger an error.)

Don’t miss : How To Print To Console Using Javascript?

So, for instance, if you have :

var demo = function () { return (2);} 
var item = new demo(); 

item will be an empty object, and not 2. (Just go through every phase.)

And so, var member = new Member() will just set member to an empty object with the property set to “Member”, as well as nothing special whatsoever, as “Member” has no prototype, & nothing inside.

I hope you get an idea about println javascript.
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Your valuable feedback, question, or comments about this article are always welcome.
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I am Jaydeep Gondaliya , a software engineer, the founder and the person running Pakainfo. I'm a full-stack developer, entrepreneur and owner of I live in India and I love to write tutorials and tips that can help to other artisan, a Passionate Blogger, who love to share the informative content on PHP, JavaScript, jQuery, Laravel, CodeIgniter, VueJS, AngularJS and Bootstrap from the early stage.

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