How to find the element in python list?

Today, We want to share with you python find element in list .In this post we will show you python find index of item in list containing string, hear for Python : How to Check if an item exists in list ? we will give you demo and example for implement.In this post, we will learn about python list contains with an example.

Python List index() – Get Index or Position of Item in List

list.index(element, start, end)


Find the index of the element

Example 1:

vowels = ['a', 'e', 'i', 'o', 'i', 'u']


index = vowels.index('e')
print('The index of e:', index)

index = vowels.index('i')

print('The index of i:', index)

Example 2: Checking if something is inside

3 in [1, 2, 3] # => True

Example 3:
Python3 program to Find elements of a
list by indices present in another list

def findElements(lst1, lst2): 
	return [lst1[i] for i in lst2] 
			 
lst1 = [10, 20, 30, 40, 50] 
lst2 = [0, 2, 4] 
print(findElements(lst1, lst2)) 

Using numpy

import numpy as np 

def findElements(lst1, lst2): 
	return list(np.array(lst1)[lst2]) 
			 
lst1 = [10, 20, 30, 40, 50] 
lst2 = [0, 2, 4] 
print(findElements(lst1, lst2)) 

Using itemgetter()

from operator import itemgetter 

def findElements(lst1, lst2): 
	return list((itemgetter(*lst2)(lst1))) 
			 
lst1 = [10, 20, 30, 40, 50] 
lst2 = [0, 2, 4] 
print(findElements(lst1, lst2)) 

Using Python map()

def findElements(lst1, lst2): 
	return list(map(lst1.__getitem__, lst2)) 
			
lst1 = [10, 20, 30, 40, 50] 
lst2 = [0, 2, 4] 
print(findElements(lst1, lst2)) 

I hope you get an idea about Finding the index of an item in a list.
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