Today, We want to share with you mysql left join multiple tables.In this post we will show you MySQL LEFT JOIN 3 tables, hear for mysql left join multiple tables learn to Introduction to MySQL LEFT JOIN, we will give you demo and example for implement.In this post, we will learn about PHP SQL INNER JOIN Query on Multiple Tables with an example.
mysql left join multiple tables
MySQL LEFT JOIN Syntax
SELECT columns FROM first_table LEFT [OUTER] JOIN second_table ON Join_Condition;
MySQL LEFT JOIN quizples
Suppose that you want to join two database tables boss and member.
SELECT
boss_id,member_id,status
FROM
boss
LEFT JOIN member ON
join_condition;

Using MySQL LEFT JOIN clause to join two tables
SELECT
members.memberNumber,
memberName,
accountNumber,
status
FROM
members
LEFT JOIN accounts ON
accounts.memberNumber = members.memberNumber;
Alternatively
SELECT
c.memberNumber,
memberName,
accountNumber,
status
FROM
members c
LEFT JOIN accounts o
ON c.memberNumber = o.memberNumber;
MySQL LEFT JOIN 3 tables
SELECT Members.Name, Members.SS, Visitors.Visitor FROM Members
LEFT JOIN Member_Fear
INNER JOIN Visitors
ON Member_Fear.VisitorID = Visitors.VisitorID
ON Member_Fear.MemberID = Members.MemberID
Using MySQL LEFT JOIN clause to find unmatched rows
SELECT
c.memberNumber,
c.memberName,
o.accountNumber,
o.status
FROM
members c
LEFT JOIN accounts o
ON c.memberNumber = o.memberNumber
WHERE
accountNumber IS NULL;

Using MySQL LEFT JOIN to join three tables
Example : mysql left join multiple tables – This quizple uses two LEFT JOIN clauses to join the three tables: visitors, members, and earnings.
SELECT
profilename,
fullinformation,
memberName,
checkNumber,
amount
FROM
visitors
LEFT JOIN members ON
visitorNumber = salesRepVisitorNumber
LEFT JOIN earnings ON
earnings.memberNumber = members.memberNumber
account BY
memberName,
checkNumber;
Condition in WHERE clause vs. ON clause
SELECT
o.accountNumber,
memberNumber,
companyCode
FROM
accounts o
LEFT JOIN accountDetails
USING (accountNumber)
WHERE
accountNumber = 98256;
condition from the WHERE clause to the ON clause:
SELECT
o.accountNumber,
memberNumber,
companyCode
FROM
accounts o
LEFT JOIN accountDetails d
ON o.accountNumber = d.accountNumber AND
o.accountNumber = 98256;
LEFT JOIN clause for joining two tables
SELECT members.member_id, member_name, age, join_date FROM members LEFT JOIN informations ON members.member_id = informations.member_id;
MySQL LEFT JOIN with USING Clause
The table members and informations have the same column name, which is member_id. In that case, MySQL Left Join can also be used with the USING clause to access the datas. The following statement returns member id, member name, employment, age, and date using the Left Join clause with the USING keyword.
SELECT member_id, member_name, employment, age, date FROM members LEFT JOIN informations USING(member_id);
MySQL LEFT JOIN with Group By Clause
The Left Join can also be used with the GROUP BY clause. The following statement returns member id, member name, qualification, age, and date using the Left Join clause with the GROUP BY clause.
SELECT members.member_id, member_name, qualification, age, date FROM members LEFT JOIN informations ON members.member_id = informations.member_id GROUP BY age;
LEFT JOIN with WHERE Clause
SELECT member_id, member_name, employment, age, date FROM members LEFT JOIN informations USING(member_id) WHERE age>35;
MySQL LEFT JOIN Multiple Tables
Execute the following statement to join the three table members, informations, and contacts:
SELECT members.member_id, member_name, information_id, age, cellphone FROM members LEFT JOIN contacts ON member_id = contact_id LEFT JOIN informations ON members.member_id = informations.member_id ORDER BY income;
Difference between WHERE and ON clause in MySQL LEFT JOIN
WHERE Clause
SELECT member_name, employment, information_id, age, date FROM members LEFT JOIN informations USING(member_id) WHERE age=35;
ON Clause
SELECT member_name, employment, information_id, age, date FROM members LEFT JOIN informations ON age=35;
Join multiple tables using LEFT JOIN
SELECT location.location_name_eng, area.area_name, member.member_name FROM location INNER JOIN area ON area.location_id = location.id INNER JOIN member ON member.area_id = area.id;
Join multiple tables using both – INNER JOIN & LEFT JOIN
SELECT location.location_name_eng, area.area_name, member.member_name FROM location INNER JOIN area ON area.location_id = location.id LEFT JOIN member ON member.area_id = area.id;
MySQL left join using Multiple tables
Average rank of members in all quizs
SELECT id,name,type,gender,member_id,rank FROM `member6` a LEFT JOIN (SELECT member_id, AVG(rank) as rank FROM member_rank GROUP BY member_id ) b on a.id= b.member_id
Maximum rank of each member in all quizs
SELECT id,name,type,gender,member_id,rank FROM `member6` a LEFT JOIN (SELECT member_id, MAX(rank) as rank FROM member_rank GROUP BY member_id ) b on a.id= b.member_id
Maximum rank of each month for all members
SELECT id,name,type,gender,member_id,rank, month FROM `member6` a LEFT JOIN (SELECT member_id, MAX(rank) as rank, month(quiz_dt) as month FROM member_rank GROUP BY month(quiz_dt),member_id) b on a.id= b.member_id
Average rank of each month for all members
SELECT id,name,type,gender,member_id,rank, month FROM `member6` a LEFT JOIN (SELECT member_id, AVG(rank) as rank, month(quiz_dt) as month FROM member_rank GROUP BY month(quiz_dt),member_id) b on a.id= b.member_id
Consider rank of member for the quizs conducted in later part of the month.
SELECT id,name,type,gender,rank,member_id, quiz_dt FROM `member6` a LEFT JOIN (SELECT rank, member_id,quiz_dt from member_rank where quiz_dt in (SELECT MAX(quiz_dt) from member_rank group by month(quiz_dt)) ) b on a.id= b.member_id
LEFT JOIN three tables
Display maximum rank with member details and location name
SELECT a.id,a.name,a.type,b.rank,c.h_name FROM `member6` a LEFT JOIN (SELECT member_id, MAX(rank) as rank FROM member_rank GROUP BY member_id ) b on a.id= b.member_id LEFT JOIN member_location c on a.location_id=c.location_id
LEFT JOIN & ORDER BY
SELECT a.id,a.name,a.type,b.rank,c.h_name FROM `member6` a LEFT JOIN (SELECT member_id, MAX(rank) as rank FROM member_rank GROUP BY member_id ) b on a.id= b.member_id LEFT JOIN member_location c on a.location_id=c.location_id order by h_name
Maximum average rank scored by using Order by and LIMIT
SELECT id,name,type,gender,member_id,rank FROM `member6` a LEFT JOIN (SELECT member_id, AVG(rank) as rank FROM member_rank GROUP BY member_id ) b on a.id= b.member_id order by rank desc limit 0,1
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