Today, We want to share with you sql unique count and use distinct in sql.In this post we will show you sql find duplicates with count in sql, hear for sql uniques count, use distinct in sql, count function in sql server we will give you demo and example for implement.In this post, we will learn about sql check for duplicates, how to delete duplicate records in sql server, count queries in sql with an example.
sql unique count and use distinct in sql
There are the Following The simple About count sql and count syntax in sql Full Information With Example and source code.
As I will cover this Post with live Working example to develop sql remove duplicates with find duplicate records in sql, so the some major files and Directory structures for this example is following below.
This big post explores SQL Count Distinct operator for eliminating the multiple data value same as like a duplicate rows/records in the sql result set.
SQL COUNT() with distinct
A any type of front-end and banckend developer required to fetch data from a SQL table with multiple conditions. Sometimes, we want to fetch all records in a table so eliminate the exists NULL values. Case 1: I need to fetch distinct student records that have placed an shop last year.
Now, go ahead as well as have a quick overview of SQL Count method.
COUNT() function with distinct conditions
SQL COUNT() method with DISTINCT conditions terminate the repetitive appearance of the same data. The DISTINCT can come only once in a given select Query.
Syntax :
COUNT(DISTINCT expr,[expr...])
//-- Aggregation method Syntax
COUNT ( { [ [ ALL | DISTINCT ] expression ] | * } )
//-- Analytic method Syntax
COUNT ( [ ALL ] { expression | * } ) OVER ( [ ] )
Arguments
Return types
use distinct in sql Return types is a int
Flow Diagram for sql unique count
SQL Count Function : IN sql unique count
I use SQL Count aggregate method to get the number of rows in the output. second Case I have a product table that holds rows for all products sold by a big it tech.. I need to know the count of products sold during the last quarter. I can use SQL Count method to return the number of rows in the particularize condition.
COUNT DISTINCT and COUNT UNIQUE functions
The COUNT DISTINCT as well as COUNT UNIQUE methods data return unique some values.
The COUNT DISTINCT method returns the total number of unique data values in the table of the column or expression, as the in-accordance simple example shows.
SELECT COUNT (DISTINCT products_no) FROM products;
If the COUNT DISTINCT methods encounters NULL values, it expectly them unless every data value in the particularize column is NULL. If every column value is NULL, the COUNT DISTINCT methods returns zero (0).
The UNIQUE keyword has the same to same meaning(Extly) as the DISTINCT keyword in COUNT methods. The UNIQUE keyword more details the database server to return the total number of DISTINCT unique non-NULL data values in the column or expression. The in-accordance simple example calls the COUNT UNIQUE methods, so it is equivalent to the preceding simple example that calls the COUNT DISTINCT methods:
SELECT COUNT (UNIQUE products_no) FROM products;
If the simple UNIQUE conditions does not specify the DISTINCT or UNIQUE keyword of the SELECT Query, the query can added multiple COUNT methods that each some put on the DISTINCT as well as UNIQUE keyword as the first specification in the parameters list, as in the in-accordance example:
SELECT COUNT (UNIQUE products_no), COUNT (DISTINCT shop_num) FROM items;Example : 1 Using COUNT and DISTINCT
SELECT COUNT(DISTINCT Title) FROM Manager.Worker; GO
here is the Sql Query Results
----------- 67 (1 row(s) affected)
Example : 2 Using COUNT(*)
SELECT COUNT(*) FROM Manager.Worker; GO
here is the Sql Query Results
----------- 290 (1 row(s) affected)
Example : 3 Using COUNT(*) with other aggregates
SELECT COUNT(*), AVG(Gift) FROM Manage.ManagePerson WHERE ManageQuota > 25777; GO
here is the Sql Query Results
----------- --------------------- 14 3472.1428 (1 row(s) affected)
Example : 4 Using the OVER conditions
SELECT DISTINCT Name
, MIN(Rate) OVER (PARTITION BY edh.CategoryID) AS salaryMin
, MAX(Rate) OVER (PARTITION BY edh.CategoryID) AS MaxSalary
, AVG(Rate) OVER (PARTITION BY edh.CategoryID) AS AvgSalary
,COUNT(edh.AssertiveEntityID) OVER (PARTITION BY edh.CategoryID) AS WorkersPerDept
FROM Manager.WorkerPayHistory AS eph
JOIN Manager.WorkerCategoryHistory AS edh
ON eph.AssertiveEntityID = edh.AssertiveEntityID
JOIN Manager.Category AS d
ON d.CategoryID = edh.CategoryID
WHERE edh.EndDate IS NULL
SOPER BY Name;
here is the Sql Query Results
Name salaryMin MaxSalary AvgSalary WorkersPerDept ----------------------------- --------------------- --------------------- --------------------- ---------------- Markihjd Excutei 10.25 17.7885 14.3884 5 officersdbs 32.6923 63.4615 40.1442 6 Enginneri 39.06 125.50 68.3034 4 shreemsti and karigardsbes 9.25 24.0385 13.0316 7 Profesi 13.4615 43.2692 23.935 10 Human Resources 13.9423 27.1394 18.0248 6 ashley kennedy datas 27.4038 50.4821 34.1586 10 Marketing 13.4615 37.50 18.4318 11 Devlopersd 6.50 84.1346 13.5537 195 Devlopersd Control 8.62 24.5192 16.7746 8 administar 9.86 30.00 18.0202 14 Based on Dataware 10.5769 28.8462 15.4647 6 sodhdi win khoaklsijdbhs 40.8654 50.4821 43.6731 4 Pakai 23.0769 72.1154 29.9719 18 sellarhe and gettingsd 9.00 19.2321 10.8718 6 taps Design 8.62 29.8462 23.5054 6 (16 row(s) affected)
SQL SELECT DISTINCT Statement
The SELECT DISTINCT sql query is used to return here only distinct unique (different) sql set.
Inside a Database table, a column often data multiple records many duplicate data values; as well as sometimes you only need to set of the different unique (distinct) data values.
SELECT DISTINCT Syntax
SELECT DISTINCT column1, column2, ... FROM db_table_name;
SELECT Example Without DISTINCT
The in-accordance SQL Query selects ALL (including the duplicates) values from the “Place” column in the “Students” table:
SELECT Place FROM Students;
and then, let us use the DISTINCT keyword with the above SELECT Query and display the output.
SELECT DISTINCT Examples
The in-accordance SQL Query selects only the DISTINCT values from the “Place” column in the “Students” table:
SELECT DISTINCT Place FROM Students;
The in-accordance SQL Query lists the number of different (distinct) student places:
SELECT COUNT(DISTINCT teacher) FROM Students;
Here is the workaround for MS Access:
SELECT Count(*) AS DistinctPlaces FROM (SELECT DISTINCT teacher FROM Students);
sql unique count Example
Example :
To retrive unique number of records from the ‘shops’ table with in-accordance conditions –
- only unique stud_code will be counted
- output will display with the heading “Number of workers”
the in-accordance SQL Query can be used :
SELECT COUNT ( DISTINCT stud_code ) AS "Number of workers" FROM shops;
Sample Database table : shops
SOP_NUM SOP_AMOUNT ADVANCE_AMOUNT SOP_DATE STUD_CODE AGENT_CODE SOP_DESCRIPTION
---------- ---------- -------------- --------- --------------- --------------- -----------------
555114 3500 5550 15-AUG-21 C77702 P021
555122 2500 400 16-SEP-21 C77703 P004
555118 500 100 20-JUL-21 C77723 P006
555119 4777 700 16-SEP-21 C77707 P010
555121 1500 600 23-SEP-21 C77721 P004
555130 2500 400 30-JUL-21 C77725 P011
555134 4555 1800 25-SEP-21 C77704 P005
555121 4777 600 15-FEB-21 C77721 P004
555103 1500 700 15-MAY-21 C77721 P005
555105 2500 500 18-JUL-21 C77725 P011
555109 3500 800 30-JUL-21 C77711 P010
555101 3777 1777 15-JUL-21 C77701 P021
555111 1777 300 10-JUL-21 C77720 P021
555104 1500 500 13-MAR-21 C77706 P004
555106 2500 700 20-APR-21 C77705 P002
555125 5550 600 10-OCT-21 C77718 P005
555117 800 555 20-OCT-21 C77714 P001
555123 500 100 16-SEP-21 C77722 P002
555120 500 100 20-JUL-21 C77709 P002
555116 500 100 13-JUL-21 C77710 P009
555124 500 100 20-JUN-21 C77717 P007
555126 500 100 24-JUN-21 C77722 P002
555129 2500 500 20-JUL-21 C77724 P006
555127 2500 400 20-JUL-21 C77715 P003
555128 3500 1500 20-JUL-21 C77709 P002
555135 5550 800 16-SEP-21 C77707 P010
555131 900 150 26-AUG-21 C77712 P012
555133 1555 400 29-JUN-21 C77709 P002
555100 1777 600 21-JAN-21 C77715 P003
555110 3777 500 15-APR-21 C77719 P010
555107 4500 900 30-AUG-21 C77707 P010
555112 5550 400 30-MAY-21 C77716 P007
555113 4777 600 10-JUN-21 C77722 P002
555102 5550 300 25-MAY-21 C77712 P012
Result this Sql Query
Output :
Number of workers
-------------------
25
sql count(distinct multiple columns)
In the in-accordance, I have Information the usage of ALL conditions with SQL COUNT() methods to count only the non NULL data value for the particularize table column within the parameters. The difference between ‘*’(asterisk) as well as ALL are, ‘*’ counts the NULL data value also but use the ALL counts only here NON NULL data value.
Example:
To get data of number of valid ‘percentage’ from the ‘student’ table with the in-accordance condition –
- every student must be a valid percentage
the in-accordance SQL Query can be used :
SELECT COUNT( ALL percentage ) FROM student;
Sample table: student
+-----------+-------------+-------------+--------------+--------------+-------+-------------+-------------+-------------+---------------+--------------+------------+ |STUD_CODE | STUD_NAME | STUD_CITY | WORKING_AREA | STUD_COUNTRY | GRADE | OPENING_AMT | RECEIVE_AMT | PAYMENT_AMT |OUTSTANDING_AMT| PHONE_NO | AGENT_CODE | +-----------+-------------+-------------+--------------+--------------+-------+-------------+-------------+-------------+---------------+--------------+------------+ | C77713 | Holmes | America | America | PK | 2 | 6777.00 | 5777.00 | 7777.00 | 4777.00 | BBBBBBB | P003 | | C77701 | Micheal | New York | New York | USA | 2 | 3777.00 | 5777.00 | 5550.00 | 6777.00 | CCCCCCC | P021 | | C77720 | Albert | New York | New York | USA | 3 | 5777.00 | 7777.00 | 6777.00 | 6777.00 | BBBBSBB | P021 | | C77725 | Ravindran | Rajkot | Rajkot | Caneda | 2 | 5777.00 | 7777.00 | 4777.00 | 8777.00 | AVAVAVA | P011 | | C77724 | Cook | America | America | PK | 2 | 4777.00 | 9777.00 | 7777.00 | 6777.00 | FSDDSDF | P006 | | C77715 | Stuart | America | America | PK | 1 | 6777.00 | 8777.00 | 3777.00 | 11777.00 | GFSGERS | P003 | | C77702 | Bolt | New York | New York | USA | 3 | 5777.00 | 7777.00 | 9777.00 | 3777.00 | DDNRDRH | P021 | | C77718 | Fleming | Brisban | Brisban | Australia | 2 | 7777.00 | 7777.00 | 9777.00 | 5777.00 | NHBGVFC | P005 | | C77721 | Jacks | Brisban | Brisban | Australia | 1 | 7777.00 | 7777.00 | 7777.00 | 7777.00 | WERTGDF | P005 | | C77719 | Yearannaidu | Bhavanagar | Bhavanagar | Caneda | 1 | 8777.00 | 7777.00 | 7777.00 | 8777.00 | ZZZZBFV | P010 | | C77705 | Sasikant | Ahemdabad | Ahemdabad | Caneda | 1 | 7777.00 | 11777.00 | 7777.00 | 11777.00 | 147-25896312 | P002 | | C77707 | Ramanathan | Bhavanagar | Bhavanagar | Caneda | 1 | 7777.00 | 11777.00 | 9777.00 | 9777.00 | GHRDWSD | P010 | | C77722 | Avinash | Ahemdabad | Ahemdabad | Caneda | 2 | 7777.00 | 11777.00 | 9777.00 | 9777.00 | 113-12345678 | P002 | | C77704 | Winston | Brisban | Brisban | Australia | 1 | 5777.00 | 8777.00 | 7777.00 | 6777.00 | AAAAAAA | P005 | | C77723 | Karl | America | America | PK | 0 | 4777.00 | 6777.00 | 7777.00 | 3777.00 | AAAABAA | P006 | | C77706 | Shilton | Surat | Surat | Canada | 1 | 17770.00 | 7777.00 | 6777.00 | 11777.00 | DDDDDDD | P004 | | C77710 | Charles | Kalavad | Kalavad | PK | 3 | 6777.00 | 4777.00 | 5777.00 | 5777.00 | MMMMMMM | P009 | | C77717 | Srinivas | Rajkot | Rajkot | Caneda | 2 | 8777.00 | 4777.00 | 3777.00 | 9777.00 | AAAAAAB | P007 | | C77712 | Steven | San Jose | San Jose | USA | 1 | 5777.00 | 7777.00 | 9777.00 | 3777.00 | KRFYGJK | P012 | | C77721 | Karolina | Surat | Surat | Canada | 1 | 7777.00 | 7777.00 | 9777.00 | 5777.00 | HJKORED | P004 | | C77703 | Martin | Surat | Surat | Canada | 2 | 8777.00 | 7777.00 | 7777.00 | 8777.00 | MJYURFD | P004 | | C77709 | Ramesh | Ahemdabad | Ahemdabad | Caneda | 3 | 8777.00 | 7777.00 | 3777.00 | 15550.00 | Phone No | P002 | | C77714 | Rangarappa | Rajkot | Rajkot | Caneda | 2 | 8777.00 | 11777.00 | 7777.00 | 15550.00 | AAAATGF | P001 | | C77716 | Venkatpati | Rajkot | Rajkot | Caneda | 2 | 8777.00 | 11777.00 | 7777.00 | 15550.00 | JRTVFDD | P007 | | C77711 | Sundariya | Bhavanagar | Bhavanagar | Caneda | 3 | 7777.00 | 11777.00 | 7777.00 | 11777.00 | PPHGRTS | P010 | +-----------+-------------+-------------+--------------+--------------+-------+-------------+-------------+-------------+---------------+--------------+------------+
Output :
Output :
COUNT(ALLGRADE)
---------------
25
Note: results of the said SQL Query Display here is taken by in Oracle Database 10g Express platform Edition.
Difference between SELECT COUNT, COUNT(*) & SQL COUNT distinct
sql unique count
|
COUNT |
Count(*) |
Count(Distinct) |
|
It returns the total number of records after fulfilling conditions particularize in the where conditions. |
It returns the total number of records after fulfilling conditions particularize in the where conditions. |
It returns the distinct number of records after fulfilling conditions particularize in the where conditions. |
|
It gives the counts of records. It does not eliminate duplicate values. |
It considers all records regardless of any duplicate, NULL values. |
It gives a distinct number of records after eliminating NULL as well as duplicate values. |
|
It terminate the NULL values in the results. |
It does not eliminate the NULL values in the results. |
It terminate the NULL values in the results. |
Here is a slide presentation of SQL SELECT SUM On Multiple INNER JOIN With Another Table.
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